Richard Joyal Module 3 Homework Chapter 4 Problems Applied conclusiveness methids 4-13: A:) [pic] B) Predict the final average of a learner who do an 83 on the fist test: y = 0.7399x + 18.989 y = 0.7399(83) + 18.989 y = 80.40 C) Give measures of r and r2 for this present. Interpret the value of r2 in the context of the problem: Â r2 = 0.8474 r = sqrt(0.8474) = 0.92054 84% of the spill in the second exam score is explained by the jump exam score. 4-15: Yes there is a correlation between the freshman test grade and the final average which lead me to intend that the first test grade is usually a clear indication of what the students over all performance will be and what their final average will be. 4-17: Accountants at the firm prosaic and walker believed that several traveling executives submit unusually go travel vouchers when they return from trips. The accounts. withalk a sample of 200 vouchers submitted tramp up year they then developed the following sevenfold relapsing equation relating expected travel cost (Y) to keep down days on the road (X1) and distance traveled (X2) in millilitres: y= $90,000+$48.50X1+$0.40X2 The coefficient of correlation computed was 0.68.

A) If thomas williams returns form a three hundred mile trip that took him of of town for 5 days, what is the expected get that he should claim as expenses? y= $90+$48.50(5)+$0.40(300) y = $452.50 B) Williams submitted a reimbursement request for $685 what should the restrainer do? The accountant should estimate a 95% prediction interval for the regression model, and let out wheth! er or not $685 falls within it. If not, then the accountant hindquarters be 95% certain that Williams expenses are too high, found on the current model. This does not necessarily remember that Williams has submitted a fraudulent report, as there may be some other common cause. C.) One possible shifting might intromit a cost-of-living index for the city visited. The model could also be divided into trips that...If you want to get a full essay, inn it on our website:
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